Algebra Beispiele

$f (x) = 10 x^{\frac{1}{5}} - 2$

Schritt 1

Schreibe $f (x) = 10 x^{\frac{1}{5}} - 2$ als Gleichung.

$y = 10 x^{\frac{1}{5}} - 2$

Schritt 2

Vertausche die Variablen.

$x = 10 y^{\frac{1}{5}} - 2$

Schritt 3

Löse nach $y$ auf.

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Schritt 3.1

Schreibe die Gleichung als $10 y^{\frac{1}{5}} - 2 = x$ um.

$10 y^{\frac{1}{5}} - 2 = x$

Schritt 3.2

Bringe alle Terme, die nicht $y$ enthalten, auf die rechte Seite der Gleichung.

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Schritt 3.2.1

Addiere $2$ zu beiden Seiten der Gleichung.

$10 y^{\frac{1}{5}} - x = 2$

Schritt 3.2.2

Addiere $x$ zu beiden Seiten der Gleichung.

$10 y^{\frac{1}{5}} = 2 + x$

Schritt 3.3

Potenziere jede Seite der Gleichung mit $5$ , um den gebrochenen Exponenten auf der linken Seite zu eliminieren.

${(10 y^{\frac{1}{5}})}^{5} = {(2 + x)}^{5}$

Schritt 3.4

Vereinfache den Exponenten.

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Schritt 3.4.1

Vereinfache die linke Seite.

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Schritt 3.4.1.1

Vereinfache ${(10 y^{\frac{1}{5}})}^{5}$ .

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Schritt 3.4.1.1.1

Wende die Produktregel auf $10 y^{\frac{1}{5}}$ an.

$10^{5} {(y^{\frac{1}{5}})}^{5} = {(2 + x)}^{5}$

Schritt 3.4.1.1.2

Potenziere $10$ mit $5$ .

$100000 {(y^{\frac{1}{5}})}^{5} = {(2 + x)}^{5}$

Schritt 3.4.1.1.3

Multipliziere die Exponenten in ${(y^{\frac{1}{5}})}^{5}$ .

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Schritt 3.4.1.1.3.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$100000 y^{\frac{1}{5} \cdot 5} = {(2 + x)}^{5}$

Schritt 3.4.1.1.3.2

Kürze den gemeinsamen Faktor von $5$ .

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Schritt 3.4.1.1.3.2.1

Kürze den gemeinsamen Faktor.

$100000 y^{\frac{1}{5} \cdot 5} = {(2 + x)}^{5}$

Schritt 3.4.1.1.3.2.2

Forme den Ausdruck um.

$100000 y^{1} = {(2 + x)}^{5}$

Schritt 3.4.1.1.4

Vereinfache.

$100000 y = {(2 + x)}^{5}$

Schritt 3.4.2

Vereinfache die rechte Seite.

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Schritt 3.4.2.1

Vereinfache ${(2 + x)}^{5}$ .

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Schritt 3.4.2.1.1

Wende den binomischen Lehrsatz an.

$100000 y = 2^{5} + 5 \cdot 2^{4} x + 10 \cdot 2^{3} x^{2} + 10 \cdot 2^{2} x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Schritt 3.4.2.1.2

Vereinfache jeden Term.

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Schritt 3.4.2.1.2.1

Potenziere $2$ mit $5$ .

$100000 y = 32 + 5 \cdot 2^{4} x + 10 \cdot 2^{3} x^{2} + 10 \cdot 2^{2} x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Schritt 3.4.2.1.2.2

Potenziere $2$ mit $4$ .

$100000 y = 32 + 5 \cdot 16 x + 10 \cdot 2^{3} x^{2} + 10 \cdot 2^{2} x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Schritt 3.4.2.1.2.3

Mutltipliziere $5$ mit $16$ .

$100000 y = 32 + 80 x + 10 \cdot 2^{3} x^{2} + 10 \cdot 2^{2} x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Schritt 3.4.2.1.2.4

Potenziere $2$ mit $3$ .

$100000 y = 32 + 80 x + 10 \cdot 8 x^{2} + 10 \cdot 2^{2} x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Schritt 3.4.2.1.2.5

Mutltipliziere $10$ mit $8$ .

$100000 y = 32 + 80 x + 80 x^{2} + 10 \cdot 2^{2} x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Schritt 3.4.2.1.2.6

Potenziere $2$ mit $2$ .

$100000 y = 32 + 80 x + 80 x^{2} + 10 \cdot 4 x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Schritt 3.4.2.1.2.7

Mutltipliziere $10$ mit $4$ .

$100000 y = 32 + 80 x + 80 x^{2} + 40 x^{3} + 5 \cdot 2 x^{4} + x^{5}$

Schritt 3.4.2.1.2.8

Mutltipliziere $5$ mit $2$ .

$100000 y = 32 + 80 x + 80 x^{2} + 40 x^{3} + 10 x^{4} + x^{5}$

Schritt 3.5

Teile jeden Ausdruck in $100000 y = 32 + 80 x + 80 x^{2} + 40 x^{3} + 10 x^{4} + x^{5}$ durch $100000$ und vereinfache.

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Schritt 3.5.1

Teile jeden Ausdruck in $100000 y = 32 + 80 x + 80 x^{2} + 40 x^{3} + 10 x^{4} + x^{5}$ durch $100000$ .

$\frac{100000 y}{100000} = \frac{32}{100000} + \frac{80 x}{100000} + \frac{80 x^{2}}{100000} + \frac{40 x^{3}}{100000} + \frac{10 x^{4}}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.2

Vereinfache die linke Seite.

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Schritt 3.5.2.1

Kürze den gemeinsamen Faktor von $100000$ .

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Schritt 3.5.2.1.1

Kürze den gemeinsamen Faktor.

$\frac{100000 y}{100000} = \frac{32}{100000} + \frac{80 x}{100000} + \frac{80 x^{2}}{100000} + \frac{40 x^{3}}{100000} + \frac{10 x^{4}}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.2.1.2

Dividiere $y$ durch $1$ .

$y = \frac{32}{100000} + \frac{80 x}{100000} + \frac{80 x^{2}}{100000} + \frac{40 x^{3}}{100000} + \frac{10 x^{4}}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.3

Vereinfache die rechte Seite.

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Schritt 3.5.3.1

Vereinfache jeden Term.

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Schritt 3.5.3.1.1

Kürze den gemeinsamen Teiler von $32$ und $100000$ .

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Schritt 3.5.3.1.1.1

Faktorisiere $32$ aus $32$ heraus.

$y = \frac{32 (1)}{100000} + \frac{80 x}{100000} + \frac{80 x^{2}}{100000} + \frac{40 x^{3}}{100000} + \frac{10 x^{4}}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.3.1.1.2

Kürze die gemeinsamen Faktoren.

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Schritt 3.5.3.1.1.2.1

Faktorisiere $32$ aus $100000$ heraus.

$y = \frac{32 \cdot 1}{32 \cdot 3125} + \frac{80 x}{100000} + \frac{80 x^{2}}{100000} + \frac{40 x^{3}}{100000} + \frac{10 x^{4}}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.3.1.1.2.2

Kürze den gemeinsamen Faktor.

$y = \frac{32 \cdot 1}{32 \cdot 3125} + \frac{80 x}{100000} + \frac{80 x^{2}}{100000} + \frac{40 x^{3}}{100000} + \frac{10 x^{4}}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.3.1.1.2.3

Forme den Ausdruck um.

$y = \frac{1}{3125} + \frac{80 x}{100000} + \frac{80 x^{2}}{100000} + \frac{40 x^{3}}{100000} + \frac{10 x^{4}}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.3.1.2

Kürze den gemeinsamen Teiler von $80$ und $100000$ .

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Schritt 3.5.3.1.2.1

Faktorisiere $80$ aus $80 x$ heraus.

$y = \frac{1}{3125} + \frac{80 (x)}{100000} + \frac{80 x^{2}}{100000} + \frac{40 x^{3}}{100000} + \frac{10 x^{4}}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.3.1.2.2

Kürze die gemeinsamen Faktoren.

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Schritt 3.5.3.1.2.2.1

Faktorisiere $80$ aus $100000$ heraus.

$y = \frac{1}{3125} + \frac{80 x}{80 \cdot 1250} + \frac{80 x^{2}}{100000} + \frac{40 x^{3}}{100000} + \frac{10 x^{4}}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.3.1.2.2.2

Kürze den gemeinsamen Faktor.

$y = \frac{1}{3125} + \frac{80 x}{80 \cdot 1250} + \frac{80 x^{2}}{100000} + \frac{40 x^{3}}{100000} + \frac{10 x^{4}}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.3.1.2.2.3

Forme den Ausdruck um.

$y = \frac{1}{3125} + \frac{x}{1250} + \frac{80 x^{2}}{100000} + \frac{40 x^{3}}{100000} + \frac{10 x^{4}}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.3.1.3

Kürze den gemeinsamen Teiler von $80$ und $100000$ .

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Schritt 3.5.3.1.3.1

Faktorisiere $80$ aus $80 x^{2}$ heraus.

$y = \frac{1}{3125} + \frac{x}{1250} + \frac{80 (x^{2})}{100000} + \frac{40 x^{3}}{100000} + \frac{10 x^{4}}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.3.1.3.2

Kürze die gemeinsamen Faktoren.

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Schritt 3.5.3.1.3.2.1

Faktorisiere $80$ aus $100000$ heraus.

$y = \frac{1}{3125} + \frac{x}{1250} + \frac{80 x^{2}}{80 \cdot 1250} + \frac{40 x^{3}}{100000} + \frac{10 x^{4}}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.3.1.3.2.2

Kürze den gemeinsamen Faktor.

$y = \frac{1}{3125} + \frac{x}{1250} + \frac{80 x^{2}}{80 \cdot 1250} + \frac{40 x^{3}}{100000} + \frac{10 x^{4}}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.3.1.3.2.3

Forme den Ausdruck um.

$y = \frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{40 x^{3}}{100000} + \frac{10 x^{4}}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.3.1.4

Kürze den gemeinsamen Teiler von $40$ und $100000$ .

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Schritt 3.5.3.1.4.1

Faktorisiere $40$ aus $40 x^{3}$ heraus.

$y = \frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{40 (x^{3})}{100000} + \frac{10 x^{4}}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.3.1.4.2

Kürze die gemeinsamen Faktoren.

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Schritt 3.5.3.1.4.2.1

Faktorisiere $40$ aus $100000$ heraus.

$y = \frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{40 x^{3}}{40 \cdot 2500} + \frac{10 x^{4}}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.3.1.4.2.2

Kürze den gemeinsamen Faktor.

$y = \frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{40 x^{3}}{40 \cdot 2500} + \frac{10 x^{4}}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.3.1.4.2.3

Forme den Ausdruck um.

$y = \frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{x^{3}}{2500} + \frac{10 x^{4}}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.3.1.5

Kürze den gemeinsamen Teiler von $10$ und $100000$ .

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Schritt 3.5.3.1.5.1

Faktorisiere $10$ aus $10 x^{4}$ heraus.

$y = \frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{x^{3}}{2500} + \frac{10 (x^{4})}{100000} + \frac{x^{5}}{100000}$

Schritt 3.5.3.1.5.2

Kürze die gemeinsamen Faktoren.

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Schritt 3.5.3.1.5.2.1

Faktorisiere $10$ aus $100000$ heraus.

$y = \frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{x^{3}}{2500} + \frac{10 x^{4}}{10 \cdot 10000} + \frac{x^{5}}{100000}$

Schritt 3.5.3.1.5.2.2

Kürze den gemeinsamen Faktor.

$y = \frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{x^{3}}{2500} + \frac{10 x^{4}}{10 \cdot 10000} + \frac{x^{5}}{100000}$

Schritt 3.5.3.1.5.2.3

Forme den Ausdruck um.

$y = \frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{x^{3}}{2500} + \frac{x^{4}}{10000} + \frac{x^{5}}{100000}$

Schritt 4

Ersetze $y$ durch $f^{- 1} (x)$ , um die endgültige Lösung anzuzeigen.

$f^{- 1} (x) = \frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{x^{3}}{2500} + \frac{x^{4}}{10000} + \frac{x^{5}}{100000}$

Schritt 5

Überprüfe, ob $f^{- 1} (x) = \frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{x^{3}}{2500} + \frac{x^{4}}{10000} + \frac{x^{5}}{100000}$ die Umkehrfunktion von $f (x) = 10 x^{\frac{1}{5}} - 2$ ist.

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Schritt 5.1

Um die inverse Funktion (Umkehrfunktion) zu prüfen, prüfe ob $f^{- 1} (f (x)) = x$ ist und $f (f^{- 1} (x)) = x$ ist.

Schritt 5.2

Berechne $f^{- 1} (f (x))$ .

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Schritt 5.2.1

Bilde die verkettete Ergebnisfunktion.

$f^{- 1} (f (x))$

Schritt 5.2.2

Berechne $f^{- 1} (10 x^{\frac{1}{5}} - 2)$ durch Einsetzen des Wertes von $f$ in $f^{- 1}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{10 x^{\frac{1}{5}} - 2}{1250} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{2}}{1250} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3

Vereinfache Terme.

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Schritt 5.2.3.1

Vereinfache jeden Term.

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Schritt 5.2.3.1.1

Faktorisiere $2$ aus $10 x^{\frac{1}{5}}$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{2 (5 x^{\frac{1}{5}}) - 2}{1250} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{2}}{1250} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.2

Faktorisiere $2$ aus $- 2$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{2 (5 x^{\frac{1}{5}}) + 2 (- 1)}{1250} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{2}}{1250} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.3

Faktorisiere $2$ aus $2 (5 x^{\frac{1}{5}}) + 2 (- 1)$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{2 (5 x^{\frac{1}{5}} - 1)}{1250} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{2}}{1250} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.4

Kürze die gemeinsamen Faktoren.

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Schritt 5.2.3.1.4.1

Faktorisiere $2$ aus $1250$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{2 (5 x^{\frac{1}{5}} - 1)}{2 (625)} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{2}}{1250} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.4.2

Kürze den gemeinsamen Faktor.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{2 (5 x^{\frac{1}{5}} - 1)}{2 \cdot 625} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{2}}{1250} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.4.3

Forme den Ausdruck um.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{2}}{1250} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.5

Vereinfache den Zähler.

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Schritt 5.2.3.1.5.1

Faktorisiere $2$ aus $10 x^{\frac{1}{5}} - 2$ heraus.

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Schritt 5.2.3.1.5.1.1

Faktorisiere $2$ aus $10 x^{\frac{1}{5}}$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{{(2 (5 x^{\frac{1}{5}}) - 2)}^{2}}{1250} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.5.1.2

Faktorisiere $2$ aus $- 2$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{{(2 (5 x^{\frac{1}{5}}) + 2 (- 1))}^{2}}{1250} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.5.1.3

Faktorisiere $2$ aus $2 (5 x^{\frac{1}{5}}) + 2 (- 1)$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{{(2 (5 x^{\frac{1}{5}} - 1))}^{2}}{1250} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.5.2

Wende die Produktregel auf $2 (5 x^{\frac{1}{5}} - 1)$ an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2^{2} {(5 x^{\frac{1}{5}} - 1)}^{2}}{1250} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.5.3

Potenziere $2$ mit $2$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{4 {(5 x^{\frac{1}{5}} - 1)}^{2}}{1250} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.6

Faktorisiere $2$ aus $4 {(5 x^{\frac{1}{5}} - 1)}^{2}$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 (2 {(5 x^{\frac{1}{5}} - 1)}^{2})}{1250} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.7

Kürze die gemeinsamen Faktoren.

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Schritt 5.2.3.1.7.1

Faktorisiere $2$ aus $1250$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 (2 {(5 x^{\frac{1}{5}} - 1)}^{2})}{2 (625)} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.7.2

Kürze den gemeinsamen Faktor.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 (2 {(5 x^{\frac{1}{5}} - 1)}^{2})}{2 \cdot 625} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.7.3

Forme den Ausdruck um.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.8

Vereinfache den Zähler.

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Schritt 5.2.3.1.8.1

Faktorisiere $2$ aus $10 x^{\frac{1}{5}} - 2$ heraus.

Tippen, um mehr Schritte zu sehen ...

Schritt 5.2.3.1.8.1.1

Faktorisiere $2$ aus $10 x^{\frac{1}{5}}$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{{(2 (5 x^{\frac{1}{5}}) - 2)}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.8.1.2

Faktorisiere $2$ aus $- 2$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{{(2 (5 x^{\frac{1}{5}}) + 2 (- 1))}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.8.1.3

Faktorisiere $2$ aus $2 (5 x^{\frac{1}{5}}) + 2 (- 1)$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{{(2 (5 x^{\frac{1}{5}} - 1))}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.8.2

Wende die Produktregel auf $2 (5 x^{\frac{1}{5}} - 1)$ an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2^{3} {(5 x^{\frac{1}{5}} - 1)}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.8.3

Potenziere $2$ mit $3$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{8 {(5 x^{\frac{1}{5}} - 1)}^{3}}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.9

Faktorisiere $4$ aus $8 {(5 x^{\frac{1}{5}} - 1)}^{3}$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{4 (2 {(5 x^{\frac{1}{5}} - 1)}^{3})}{2500} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.10

Kürze die gemeinsamen Faktoren.

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Schritt 5.2.3.1.10.1

Faktorisiere $4$ aus $2500$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{4 (2 {(5 x^{\frac{1}{5}} - 1)}^{3})}{4 (625)} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.10.2

Kürze den gemeinsamen Faktor.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{4 (2 {(5 x^{\frac{1}{5}} - 1)}^{3})}{4 \cdot 625} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.10.3

Forme den Ausdruck um.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{3}}{625} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.11

Vereinfache den Zähler.

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Schritt 5.2.3.1.11.1

Faktorisiere $2$ aus $10 x^{\frac{1}{5}} - 2$ heraus.

Tippen, um mehr Schritte zu sehen ...

Schritt 5.2.3.1.11.1.1

Faktorisiere $2$ aus $10 x^{\frac{1}{5}}$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{3}}{625} + \frac{{(2 (5 x^{\frac{1}{5}}) - 2)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.11.1.2

Faktorisiere $2$ aus $- 2$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{3}}{625} + \frac{{(2 (5 x^{\frac{1}{5}}) + 2 (- 1))}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.11.1.3

Faktorisiere $2$ aus $2 (5 x^{\frac{1}{5}}) + 2 (- 1)$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{3}}{625} + \frac{{(2 (5 x^{\frac{1}{5}} - 1))}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.11.2

Wende die Produktregel auf $2 (5 x^{\frac{1}{5}} - 1)$ an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{3}}{625} + \frac{2^{4} {(5 x^{\frac{1}{5}} - 1)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.11.3

Potenziere $2$ mit $4$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{3}}{625} + \frac{16 {(5 x^{\frac{1}{5}} - 1)}^{4}}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.12

Faktorisiere $16$ aus $16 {(5 x^{\frac{1}{5}} - 1)}^{4}$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{3}}{625} + \frac{16 ({(5 x^{\frac{1}{5}} - 1)}^{4})}{10000} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.13

Kürze die gemeinsamen Faktoren.

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Schritt 5.2.3.1.13.1

Faktorisiere $16$ aus $10000$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{3}}{625} + \frac{16 {(5 x^{\frac{1}{5}} - 1)}^{4}}{16 \cdot 625} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.13.2

Kürze den gemeinsamen Faktor.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{3}}{625} + \frac{16 {(5 x^{\frac{1}{5}} - 1)}^{4}}{16 \cdot 625} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.13.3

Forme den Ausdruck um.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{3}}{625} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{4}}{625} + \frac{{(10 x^{\frac{1}{5}} - 2)}^{5}}{100000}$

Schritt 5.2.3.1.14

Vereinfache den Zähler.

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Schritt 5.2.3.1.14.1

Faktorisiere $2$ aus $10 x^{\frac{1}{5}} - 2$ heraus.

Tippen, um mehr Schritte zu sehen ...

Schritt 5.2.3.1.14.1.1

Faktorisiere $2$ aus $10 x^{\frac{1}{5}}$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{3}}{625} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{4}}{625} + \frac{{(2 (5 x^{\frac{1}{5}}) - 2)}^{5}}{100000}$

Schritt 5.2.3.1.14.1.2

Faktorisiere $2$ aus $- 2$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{3}}{625} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{4}}{625} + \frac{{(2 (5 x^{\frac{1}{5}}) + 2 (- 1))}^{5}}{100000}$

Schritt 5.2.3.1.14.1.3

Faktorisiere $2$ aus $2 (5 x^{\frac{1}{5}}) + 2 (- 1)$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{3}}{625} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{4}}{625} + \frac{{(2 (5 x^{\frac{1}{5}} - 1))}^{5}}{100000}$

Schritt 5.2.3.1.14.2

Wende die Produktregel auf $2 (5 x^{\frac{1}{5}} - 1)$ an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{3}}{625} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{4}}{625} + \frac{2^{5} {(5 x^{\frac{1}{5}} - 1)}^{5}}{100000}$

Schritt 5.2.3.1.14.3

Potenziere $2$ mit $5$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{3}}{625} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{4}}{625} + \frac{32 {(5 x^{\frac{1}{5}} - 1)}^{5}}{100000}$

Schritt 5.2.3.1.15

Faktorisiere $32$ aus $32 {(5 x^{\frac{1}{5}} - 1)}^{5}$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{3}}{625} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{4}}{625} + \frac{32 ({(5 x^{\frac{1}{5}} - 1)}^{5})}{100000}$

Schritt 5.2.3.1.16

Kürze die gemeinsamen Faktoren.

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Schritt 5.2.3.1.16.1

Faktorisiere $32$ aus $100000$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{3}}{625} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{4}}{625} + \frac{32 {(5 x^{\frac{1}{5}} - 1)}^{5}}{32 \cdot 3125}$

Schritt 5.2.3.1.16.2

Kürze den gemeinsamen Faktor.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{3}}{625} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{4}}{625} + \frac{32 {(5 x^{\frac{1}{5}} - 1)}^{5}}{32 \cdot 3125}$

Schritt 5.2.3.1.16.3

Forme den Ausdruck um.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{5 x^{\frac{1}{5}} - 1}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{2}}{625} + \frac{2 {(5 x^{\frac{1}{5}} - 1)}^{3}}{625} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{4}}{625} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125}$

Schritt 5.2.3.2

Vereinige die Zähler über dem gemeinsamen Nenner.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 2 {(5 x^{\frac{1}{5}} - 1)}^{2} + 2 {(5 x^{\frac{1}{5}} - 1)}^{3} + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3

Vereinfache jeden Term.

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Schritt 5.2.3.3.1

Schreibe ${(5 x^{\frac{1}{5}} - 1)}^{2}$ als $(5 x^{\frac{1}{5}} - 1) (5 x^{\frac{1}{5}} - 1)$ um.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 2 ((5 x^{\frac{1}{5}} - 1) (5 x^{\frac{1}{5}} - 1)) + 2 {(5 x^{\frac{1}{5}} - 1)}^{3} + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.2

Multipliziere $(5 x^{\frac{1}{5}} - 1) (5 x^{\frac{1}{5}} - 1)$ aus unter Verwendung der FOIL-Methode.

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Schritt 5.2.3.3.2.1

Wende das Distributivgesetz an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 2 (5 x^{\frac{1}{5}} (5 x^{\frac{1}{5}} - 1) - 1 (5 x^{\frac{1}{5}} - 1)) + 2 {(5 x^{\frac{1}{5}} - 1)}^{3} + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.2.2

Wende das Distributivgesetz an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 2 (5 x^{\frac{1}{5}} (5 x^{\frac{1}{5}}) + 5 x^{\frac{1}{5}} \cdot - 1 - 1 (5 x^{\frac{1}{5}} - 1)) + 2 {(5 x^{\frac{1}{5}} - 1)}^{3} + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.2.3

Wende das Distributivgesetz an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 2 (5 x^{\frac{1}{5}} (5 x^{\frac{1}{5}}) + 5 x^{\frac{1}{5}} \cdot - 1 - 1 (5 x^{\frac{1}{5}}) - 1 \cdot - 1) + 2 {(5 x^{\frac{1}{5}} - 1)}^{3} + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.3

Vereinfache und fasse gleichartige Terme zusammen.

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Schritt 5.2.3.3.3.1

Vereinfache jeden Term.

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Schritt 5.2.3.3.3.1.1

Schreibe neu unter Anwendung des Kommutativgesetzes der Multiplikation.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 2 (5 \cdot (5 x^{\frac{1}{5}} x^{\frac{1}{5}}) + 5 x^{\frac{1}{5}} \cdot - 1 - 1 (5 x^{\frac{1}{5}}) - 1 \cdot - 1) + 2 {(5 x^{\frac{1}{5}} - 1)}^{3} + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.3.1.2

Multipliziere $x^{\frac{1}{5}}$ mit $x^{\frac{1}{5}}$ durch Addieren der Exponenten.

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Schritt 5.2.3.3.3.1.2.1

Bewege $x^{\frac{1}{5}}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 2 (5 \cdot (5 (x^{\frac{1}{5}} x^{\frac{1}{5}})) + 5 x^{\frac{1}{5}} \cdot - 1 - 1 (5 x^{\frac{1}{5}}) - 1 \cdot - 1) + 2 {(5 x^{\frac{1}{5}} - 1)}^{3} + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.3.1.2.2

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 2 (5 \cdot (5 x^{\frac{1}{5} + \frac{1}{5}}) + 5 x^{\frac{1}{5}} \cdot - 1 - 1 (5 x^{\frac{1}{5}}) - 1 \cdot - 1) + 2 {(5 x^{\frac{1}{5}} - 1)}^{3} + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.3.1.2.3

Vereinige die Zähler über dem gemeinsamen Nenner.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 2 (5 \cdot (5 x^{\frac{1 + 1}{5}}) + 5 x^{\frac{1}{5}} \cdot - 1 - 1 (5 x^{\frac{1}{5}}) - 1 \cdot - 1) + 2 {(5 x^{\frac{1}{5}} - 1)}^{3} + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.3.1.2.4

Addiere $1$ und $1$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 2 (5 \cdot (5 x^{\frac{2}{5}}) + 5 x^{\frac{1}{5}} \cdot - 1 - 1 (5 x^{\frac{1}{5}}) - 1 \cdot - 1) + 2 {(5 x^{\frac{1}{5}} - 1)}^{3} + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.3.1.3

Mutltipliziere $5$ mit $5$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 2 (25 x^{\frac{2}{5}} + 5 x^{\frac{1}{5}} \cdot - 1 - 1 (5 x^{\frac{1}{5}}) - 1 \cdot - 1) + 2 {(5 x^{\frac{1}{5}} - 1)}^{3} + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.3.1.4

Mutltipliziere $- 1$ mit $5$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 2 (25 x^{\frac{2}{5}} - 5 x^{\frac{1}{5}} - 1 (5 x^{\frac{1}{5}}) - 1 \cdot - 1) + 2 {(5 x^{\frac{1}{5}} - 1)}^{3} + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.3.1.5

Mutltipliziere $5$ mit $- 1$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 2 (25 x^{\frac{2}{5}} - 5 x^{\frac{1}{5}} - 5 x^{\frac{1}{5}} - 1 \cdot - 1) + 2 {(5 x^{\frac{1}{5}} - 1)}^{3} + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.3.1.6

Mutltipliziere $- 1$ mit $- 1$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 2 (25 x^{\frac{2}{5}} - 5 x^{\frac{1}{5}} - 5 x^{\frac{1}{5}} + 1) + 2 {(5 x^{\frac{1}{5}} - 1)}^{3} + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.3.2

Subtrahiere $5 x^{\frac{1}{5}}$ von $- 5 x^{\frac{1}{5}}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 2 (25 x^{\frac{2}{5}} - 10 x^{\frac{1}{5}} + 1) + 2 {(5 x^{\frac{1}{5}} - 1)}^{3} + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.4

Wende das Distributivgesetz an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 2 (25 x^{\frac{2}{5}}) + 2 (- 10 x^{\frac{1}{5}}) + 2 \cdot 1 + 2 {(5 x^{\frac{1}{5}} - 1)}^{3} + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.5

Vereinfache.

Tippen, um mehr Schritte zu sehen ...

Schritt 5.2.3.3.5.1

Mutltipliziere $25$ mit $2$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} + 2 (- 10 x^{\frac{1}{5}}) + 2 \cdot 1 + 2 {(5 x^{\frac{1}{5}} - 1)}^{3} + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.5.2

Mutltipliziere $- 10$ mit $2$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 \cdot 1 + 2 {(5 x^{\frac{1}{5}} - 1)}^{3} + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.5.3

Mutltipliziere $2$ mit $1$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 2 {(5 x^{\frac{1}{5}} - 1)}^{3} + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.6

Wende den binomischen Lehrsatz an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 2 ({(5 x^{\frac{1}{5}})}^{3} + 3 {(5 x^{\frac{1}{5}})}^{2} \cdot - 1 + 3 (5 x^{\frac{1}{5}}) {(- 1)}^{2} + {(- 1)}^{3}) + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.7

Vereinfache jeden Term.

Tippen, um mehr Schritte zu sehen ...

Schritt 5.2.3.3.7.1

Wende die Produktregel auf $5 x^{\frac{1}{5}}$ an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 2 (5^{3} {(x^{\frac{1}{5}})}^{3} + 3 {(5 x^{\frac{1}{5}})}^{2} \cdot - 1 + 3 (5 x^{\frac{1}{5}}) {(- 1)}^{2} + {(- 1)}^{3}) + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.7.2

Potenziere $5$ mit $3$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 2 (125 {(x^{\frac{1}{5}})}^{3} + 3 {(5 x^{\frac{1}{5}})}^{2} \cdot - 1 + 3 (5 x^{\frac{1}{5}}) {(- 1)}^{2} + {(- 1)}^{3}) + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.7.3

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{3}$ .

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Schritt 5.2.3.3.7.3.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 2 (125 x^{\frac{1}{5} \cdot 3} + 3 {(5 x^{\frac{1}{5}})}^{2} \cdot - 1 + 3 (5 x^{\frac{1}{5}}) {(- 1)}^{2} + {(- 1)}^{3}) + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.7.3.2

Kombiniere $\frac{1}{5}$ und $3$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 2 (125 x^{\frac{3}{5}} + 3 {(5 x^{\frac{1}{5}})}^{2} \cdot - 1 + 3 (5 x^{\frac{1}{5}}) {(- 1)}^{2} + {(- 1)}^{3}) + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.7.4

Wende die Produktregel auf $5 x^{\frac{1}{5}}$ an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 2 (125 x^{\frac{3}{5}} + 3 (5^{2} {(x^{\frac{1}{5}})}^{2}) \cdot - 1 + 3 (5 x^{\frac{1}{5}}) {(- 1)}^{2} + {(- 1)}^{3}) + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.7.5

Potenziere $5$ mit $2$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 2 (125 x^{\frac{3}{5}} + 3 (25 {(x^{\frac{1}{5}})}^{2}) \cdot - 1 + 3 (5 x^{\frac{1}{5}}) {(- 1)}^{2} + {(- 1)}^{3}) + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.7.6

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{2}$ .

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Schritt 5.2.3.3.7.6.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 2 (125 x^{\frac{3}{5}} + 3 (25 x^{\frac{1}{5} \cdot 2}) \cdot - 1 + 3 (5 x^{\frac{1}{5}}) {(- 1)}^{2} + {(- 1)}^{3}) + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.7.6.2

Kombiniere $\frac{1}{5}$ und $2$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 2 (125 x^{\frac{3}{5}} + 3 (25 x^{\frac{2}{5}}) \cdot - 1 + 3 (5 x^{\frac{1}{5}}) {(- 1)}^{2} + {(- 1)}^{3}) + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.7.7

Mutltipliziere $25$ mit $3$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 2 (125 x^{\frac{3}{5}} + 75 x^{\frac{2}{5}} \cdot - 1 + 3 (5 x^{\frac{1}{5}}) {(- 1)}^{2} + {(- 1)}^{3}) + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.7.8

Mutltipliziere $- 1$ mit $75$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 2 (125 x^{\frac{3}{5}} - 75 x^{\frac{2}{5}} + 3 (5 x^{\frac{1}{5}}) {(- 1)}^{2} + {(- 1)}^{3}) + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.7.9

Mutltipliziere $5$ mit $3$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 2 (125 x^{\frac{3}{5}} - 75 x^{\frac{2}{5}} + 15 x^{\frac{1}{5}} {(- 1)}^{2} + {(- 1)}^{3}) + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.7.10

Potenziere $- 1$ mit $2$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 2 (125 x^{\frac{3}{5}} - 75 x^{\frac{2}{5}} + 15 x^{\frac{1}{5}} \cdot 1 + {(- 1)}^{3}) + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.7.11

Mutltipliziere $15$ mit $1$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 2 (125 x^{\frac{3}{5}} - 75 x^{\frac{2}{5}} + 15 x^{\frac{1}{5}} + {(- 1)}^{3}) + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.7.12

Potenziere $- 1$ mit $3$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 2 (125 x^{\frac{3}{5}} - 75 x^{\frac{2}{5}} + 15 x^{\frac{1}{5}} - 1) + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.8

Wende das Distributivgesetz an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 2 (125 x^{\frac{3}{5}}) + 2 (- 75 x^{\frac{2}{5}}) + 2 (15 x^{\frac{1}{5}}) + 2 \cdot - 1 + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.9

Vereinfache.

Tippen, um mehr Schritte zu sehen ...

Schritt 5.2.3.3.9.1

Mutltipliziere $125$ mit $2$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} + 2 (- 75 x^{\frac{2}{5}}) + 2 (15 x^{\frac{1}{5}}) + 2 \cdot - 1 + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.9.2

Mutltipliziere $- 75$ mit $2$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 2 (15 x^{\frac{1}{5}}) + 2 \cdot - 1 + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.9.3

Mutltipliziere $15$ mit $2$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} + 2 \cdot - 1 + {(5 x^{\frac{1}{5}} - 1)}^{4}}{625}$

Schritt 5.2.3.3.9.4

Mutltipliziere $2$ mit $- 1$ .

Schritt 5.2.3.3.10

Wende den binomischen Lehrsatz an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + {(5 x^{\frac{1}{5}})}^{4} + 4 {(5 x^{\frac{1}{5}})}^{3} \cdot - 1 + 6 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 (5 x^{\frac{1}{5}}) {(- 1)}^{3} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11

Vereinfache jeden Term.

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Schritt 5.2.3.3.11.1

Wende die Produktregel auf $5 x^{\frac{1}{5}}$ an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 5^{4} {(x^{\frac{1}{5}})}^{4} + 4 {(5 x^{\frac{1}{5}})}^{3} \cdot - 1 + 6 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 (5 x^{\frac{1}{5}}) {(- 1)}^{3} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.2

Potenziere $5$ mit $4$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 {(x^{\frac{1}{5}})}^{4} + 4 {(5 x^{\frac{1}{5}})}^{3} \cdot - 1 + 6 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 (5 x^{\frac{1}{5}}) {(- 1)}^{3} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.3

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{4}$ .

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Schritt 5.2.3.3.11.3.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{1}{5} \cdot 4} + 4 {(5 x^{\frac{1}{5}})}^{3} \cdot - 1 + 6 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 (5 x^{\frac{1}{5}}) {(- 1)}^{3} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.3.2

Kombiniere $\frac{1}{5}$ und $4$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{4}{5}} + 4 {(5 x^{\frac{1}{5}})}^{3} \cdot - 1 + 6 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 (5 x^{\frac{1}{5}}) {(- 1)}^{3} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.4

Wende die Produktregel auf $5 x^{\frac{1}{5}}$ an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{4}{5}} + 4 (5^{3} {(x^{\frac{1}{5}})}^{3}) \cdot - 1 + 6 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 (5 x^{\frac{1}{5}}) {(- 1)}^{3} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.5

Potenziere $5$ mit $3$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{4}{5}} + 4 (125 {(x^{\frac{1}{5}})}^{3}) \cdot - 1 + 6 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 (5 x^{\frac{1}{5}}) {(- 1)}^{3} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.6

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{3}$ .

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Schritt 5.2.3.3.11.6.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{4}{5}} + 4 (125 x^{\frac{1}{5} \cdot 3}) \cdot - 1 + 6 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 (5 x^{\frac{1}{5}}) {(- 1)}^{3} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.6.2

Kombiniere $\frac{1}{5}$ und $3$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{4}{5}} + 4 (125 x^{\frac{3}{5}}) \cdot - 1 + 6 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 (5 x^{\frac{1}{5}}) {(- 1)}^{3} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.7

Mutltipliziere $125$ mit $4$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{4}{5}} + 500 x^{\frac{3}{5}} \cdot - 1 + 6 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 (5 x^{\frac{1}{5}}) {(- 1)}^{3} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.8

Mutltipliziere $- 1$ mit $500$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} + 6 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{2} + 4 (5 x^{\frac{1}{5}}) {(- 1)}^{3} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.9

Wende die Produktregel auf $5 x^{\frac{1}{5}}$ an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} + 6 (5^{2} {(x^{\frac{1}{5}})}^{2}) {(- 1)}^{2} + 4 (5 x^{\frac{1}{5}}) {(- 1)}^{3} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.10

Potenziere $5$ mit $2$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} + 6 (25 {(x^{\frac{1}{5}})}^{2}) {(- 1)}^{2} + 4 (5 x^{\frac{1}{5}}) {(- 1)}^{3} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.11

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{2}$ .

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Schritt 5.2.3.3.11.11.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} + 6 (25 x^{\frac{1}{5} \cdot 2}) {(- 1)}^{2} + 4 (5 x^{\frac{1}{5}}) {(- 1)}^{3} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.11.2

Kombiniere $\frac{1}{5}$ und $2$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} + 6 (25 x^{\frac{2}{5}}) {(- 1)}^{2} + 4 (5 x^{\frac{1}{5}}) {(- 1)}^{3} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.12

Mutltipliziere $25$ mit $6$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} + 150 x^{\frac{2}{5}} {(- 1)}^{2} + 4 (5 x^{\frac{1}{5}}) {(- 1)}^{3} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.13

Potenziere $- 1$ mit $2$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} + 150 x^{\frac{2}{5}} \cdot 1 + 4 (5 x^{\frac{1}{5}}) {(- 1)}^{3} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.14

Mutltipliziere $150$ mit $1$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} + 150 x^{\frac{2}{5}} + 4 (5 x^{\frac{1}{5}}) {(- 1)}^{3} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.15

Mutltipliziere $5$ mit $4$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} + 150 x^{\frac{2}{5}} + 20 x^{\frac{1}{5}} {(- 1)}^{3} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.16

Potenziere $- 1$ mit $3$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} + 150 x^{\frac{2}{5}} + 20 x^{\frac{1}{5}} \cdot - 1 + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.17

Mutltipliziere $- 1$ mit $20$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} + 150 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + {(- 1)}^{4}}{625}$

Schritt 5.2.3.3.11.18

Potenziere $- 1$ mit $4$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} + 150 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 1}{625}$

Schritt 5.2.3.4

Vereinfache durch Addieren von Termen.

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Schritt 5.2.3.4.1

Vereine die Terme mit entgegengesetztem Vorzeichen in $5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 2 + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} - 2 + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} + 150 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 1$ .

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Schritt 5.2.3.4.1.1

Subtrahiere $2$ von $2$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} + 0 + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} + 150 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 1}{625}$

Schritt 5.2.3.4.1.2

Addiere $5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}}$ und $0$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 250 x^{\frac{3}{5}} - 150 x^{\frac{2}{5}} + 30 x^{\frac{1}{5}} + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} + 150 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 1}{625}$

Schritt 5.2.3.4.1.3

Addiere $- 150 x^{\frac{2}{5}}$ und $150 x^{\frac{2}{5}}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 250 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} + 0 - 20 x^{\frac{1}{5}} + 1}{625}$

Schritt 5.2.3.4.1.4

Addiere $5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 250 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}}$ und $0$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} - 1 + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 250 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + 1}{625}$

Schritt 5.2.3.4.1.5

Addiere $- 1$ und $1$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 250 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}} + 0}{625}$

Schritt 5.2.3.4.1.6

Addiere $5 x^{\frac{1}{5}} + 50 x^{\frac{2}{5}} - 20 x^{\frac{1}{5}} + 250 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}}$ und $0$ .

Schritt 5.2.3.4.2

Subtrahiere $20 x^{\frac{1}{5}}$ von $5 x^{\frac{1}{5}}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{50 x^{\frac{2}{5}} - 15 x^{\frac{1}{5}} + 250 x^{\frac{3}{5}} + 30 x^{\frac{1}{5}} + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}}}{625}$

Schritt 5.2.3.4.3

Addiere $- 15 x^{\frac{1}{5}}$ und $30 x^{\frac{1}{5}}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{50 x^{\frac{2}{5}} + 250 x^{\frac{3}{5}} + 15 x^{\frac{1}{5}} + 625 x^{\frac{4}{5}} - 500 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}}}{625}$

Schritt 5.2.3.4.4

Subtrahiere $500 x^{\frac{3}{5}}$ von $250 x^{\frac{3}{5}}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{50 x^{\frac{2}{5}} + 15 x^{\frac{1}{5}} + 625 x^{\frac{4}{5}} - 250 x^{\frac{3}{5}} - 20 x^{\frac{1}{5}}}{625}$

Schritt 5.2.3.4.5

Subtrahiere $20 x^{\frac{1}{5}}$ von $15 x^{\frac{1}{5}}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{50 x^{\frac{2}{5}} - 5 x^{\frac{1}{5}} + 625 x^{\frac{4}{5}} - 250 x^{\frac{3}{5}}}{625}$

Schritt 5.2.3.5

Vereinfache jeden Term.

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Schritt 5.2.3.5.1

Vereinfache den Zähler.

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Schritt 5.2.3.5.1.1

Faktorisiere $5 x^{\frac{1}{5}}$ aus $50 x^{\frac{2}{5}} - 5 x^{\frac{1}{5}} + 625 x^{\frac{4}{5}} - 250 x^{\frac{3}{5}}$ heraus.

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Schritt 5.2.3.5.1.1.1

Faktorisiere $5 x^{\frac{1}{5}}$ aus $50 x^{\frac{2}{5}}$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} (10 x^{\frac{1}{5}}) - 5 x^{\frac{1}{5}} + 625 x^{\frac{4}{5}} - 250 x^{\frac{3}{5}}}{625}$

Schritt 5.2.3.5.1.1.2

Faktorisiere $5 x^{\frac{1}{5}}$ aus $- 5 x^{\frac{1}{5}}$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} (10 x^{\frac{1}{5}}) + 5 x^{\frac{1}{5}} (- 1) + 625 x^{\frac{4}{5}} - 250 x^{\frac{3}{5}}}{625}$

Schritt 5.2.3.5.1.1.3

Faktorisiere $5 x^{\frac{1}{5}}$ aus $625 x^{\frac{4}{5}}$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} (10 x^{\frac{1}{5}}) + 5 x^{\frac{1}{5}} (- 1) + 5 x^{\frac{1}{5}} (125 x^{\frac{3}{5}}) - 250 x^{\frac{3}{5}}}{625}$

Schritt 5.2.3.5.1.1.4

Faktorisiere $5 x^{\frac{1}{5}}$ aus $- 250 x^{\frac{3}{5}}$ heraus.

Schritt 5.2.3.5.1.1.5

Faktorisiere $5 x^{\frac{1}{5}}$ aus $5 x^{\frac{1}{5}} (10 x^{\frac{1}{5}}) + 5 x^{\frac{1}{5}} (- 1)$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} (10 x^{\frac{1}{5}} - 1) + 5 x^{\frac{1}{5}} (125 x^{\frac{3}{5}}) + 5 x^{\frac{1}{5}} (- 50 x^{\frac{2}{5}})}{625}$

Schritt 5.2.3.5.1.1.6

Faktorisiere $5 x^{\frac{1}{5}}$ aus $5 x^{\frac{1}{5}} (10 x^{\frac{1}{5}} - 1) + 5 x^{\frac{1}{5}} (125 x^{\frac{3}{5}})$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} (10 x^{\frac{1}{5}} - 1 + 125 x^{\frac{3}{5}}) + 5 x^{\frac{1}{5}} (- 50 x^{\frac{2}{5}})}{625}$

Schritt 5.2.3.5.1.1.7

Faktorisiere $5 x^{\frac{1}{5}}$ aus $5 x^{\frac{1}{5}} (10 x^{\frac{1}{5}} - 1 + 125 x^{\frac{3}{5}}) + 5 x^{\frac{1}{5}} (- 50 x^{\frac{2}{5}})$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} (10 x^{\frac{1}{5}} - 1 + 125 x^{\frac{3}{5}} - 50 x^{\frac{2}{5}})}{625}$

Schritt 5.2.3.5.1.2

Stelle die Terme um.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{625}$

Schritt 5.2.3.5.2

Faktorisiere $5$ aus $5 x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 (x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1))}{625}$

Schritt 5.2.3.5.3

Kürze die gemeinsamen Faktoren.

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Schritt 5.2.3.5.3.1

Faktorisiere $5$ aus $625$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{5 (x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1))}{5 \cdot 125}$

Schritt 5.2.3.5.3.2

Kürze den gemeinsamen Faktor.

Schritt 5.2.3.5.3.3

Forme den Ausdruck um.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1}{3125} + \frac{{(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.6

Vereinige die Zähler über dem gemeinsamen Nenner.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + {(5 x^{\frac{1}{5}} - 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7

Vereinfache jeden Term.

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Schritt 5.2.3.7.1

Vereinfache den Zähler.

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Schritt 5.2.3.7.1.1

Wende den binomischen Lehrsatz an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + {(5 x^{\frac{1}{5}})}^{5} + 5 {(5 x^{\frac{1}{5}})}^{4} \cdot - 1 + 10 {(5 x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2

Vereinfache jeden Term.

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Schritt 5.2.3.7.1.2.1

Wende die Produktregel auf $5 x^{\frac{1}{5}}$ an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 5^{5} {(x^{\frac{1}{5}})}^{5} + 5 {(5 x^{\frac{1}{5}})}^{4} \cdot - 1 + 10 {(5 x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.2

Potenziere $5$ mit $5$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 {(x^{\frac{1}{5}})}^{5} + 5 {(5 x^{\frac{1}{5}})}^{4} \cdot - 1 + 10 {(5 x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.3

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{5}$ .

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Schritt 5.2.3.7.1.2.3.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x^{\frac{1}{5} \cdot 5} + 5 {(5 x^{\frac{1}{5}})}^{4} \cdot - 1 + 10 {(5 x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.3.2

Kürze den gemeinsamen Faktor von $5$ .

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Schritt 5.2.3.7.1.2.3.2.1

Kürze den gemeinsamen Faktor.

Schritt 5.2.3.7.1.2.3.2.2

Forme den Ausdruck um.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x + 5 {(5 x^{\frac{1}{5}})}^{4} \cdot - 1 + 10 {(5 x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.4

Vereinfache.

Schritt 5.2.3.7.1.2.5

Wende die Produktregel auf $5 x^{\frac{1}{5}}$ an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x + 5 (5^{4} {(x^{\frac{1}{5}})}^{4}) \cdot - 1 + 10 {(5 x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.6

Multipliziere $5$ mit $5^{4}$ durch Addieren der Exponenten.

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Schritt 5.2.3.7.1.2.6.1

Bewege $5^{4}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x + 5^{4} \cdot (5 {(x^{\frac{1}{5}})}^{4}) \cdot - 1 + 10 {(5 x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.6.2

Mutltipliziere $5^{4}$ mit $5$ .

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Schritt 5.2.3.7.1.2.6.2.1

Potenziere $5$ mit $1$ .

Schritt 5.2.3.7.1.2.6.2.2

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x + 5^{4 + 1} {(x^{\frac{1}{5}})}^{4} \cdot - 1 + 10 {(5 x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.6.3

Addiere $4$ und $1$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x + 5^{5} {(x^{\frac{1}{5}})}^{4} \cdot - 1 + 10 {(5 x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.7

Potenziere $5$ mit $5$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x + 3125 {(x^{\frac{1}{5}})}^{4} \cdot - 1 + 10 {(5 x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.8

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{4}$ .

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Schritt 5.2.3.7.1.2.8.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x + 3125 x^{\frac{1}{5} \cdot 4} \cdot - 1 + 10 {(5 x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.8.2

Kombiniere $\frac{1}{5}$ und $4$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x + 3125 x^{\frac{4}{5}} \cdot - 1 + 10 {(5 x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.9

Mutltipliziere $- 1$ mit $3125$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x - 3125 x^{\frac{4}{5}} + 10 {(5 x^{\frac{1}{5}})}^{3} {(- 1)}^{2} + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.10

Wende die Produktregel auf $5 x^{\frac{1}{5}}$ an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x - 3125 x^{\frac{4}{5}} + 10 (5^{3} {(x^{\frac{1}{5}})}^{3}) {(- 1)}^{2} + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.11

Potenziere $5$ mit $3$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x - 3125 x^{\frac{4}{5}} + 10 (125 {(x^{\frac{1}{5}})}^{3}) {(- 1)}^{2} + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.12

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{3}$ .

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Schritt 5.2.3.7.1.2.12.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x - 3125 x^{\frac{4}{5}} + 10 (125 x^{\frac{1}{5} \cdot 3}) {(- 1)}^{2} + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.12.2

Kombiniere $\frac{1}{5}$ und $3$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x - 3125 x^{\frac{4}{5}} + 10 (125 x^{\frac{3}{5}}) {(- 1)}^{2} + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.13

Mutltipliziere $125$ mit $10$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x - 3125 x^{\frac{4}{5}} + 1250 x^{\frac{3}{5}} {(- 1)}^{2} + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.14

Potenziere $- 1$ mit $2$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x - 3125 x^{\frac{4}{5}} + 1250 x^{\frac{3}{5}} \cdot 1 + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.15

Mutltipliziere $1250$ mit $1$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x - 3125 x^{\frac{4}{5}} + 1250 x^{\frac{3}{5}} + 10 {(5 x^{\frac{1}{5}})}^{2} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.16

Wende die Produktregel auf $5 x^{\frac{1}{5}}$ an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x - 3125 x^{\frac{4}{5}} + 1250 x^{\frac{3}{5}} + 10 (5^{2} {(x^{\frac{1}{5}})}^{2}) {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.17

Potenziere $5$ mit $2$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x - 3125 x^{\frac{4}{5}} + 1250 x^{\frac{3}{5}} + 10 (25 {(x^{\frac{1}{5}})}^{2}) {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.18

Multipliziere die Exponenten in ${(x^{\frac{1}{5}})}^{2}$ .

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Schritt 5.2.3.7.1.2.18.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x - 3125 x^{\frac{4}{5}} + 1250 x^{\frac{3}{5}} + 10 (25 x^{\frac{1}{5} \cdot 2}) {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.18.2

Kombiniere $\frac{1}{5}$ und $2$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x - 3125 x^{\frac{4}{5}} + 1250 x^{\frac{3}{5}} + 10 (25 x^{\frac{2}{5}}) {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.19

Mutltipliziere $25$ mit $10$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x - 3125 x^{\frac{4}{5}} + 1250 x^{\frac{3}{5}} + 250 x^{\frac{2}{5}} {(- 1)}^{3} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.20

Potenziere $- 1$ mit $3$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x - 3125 x^{\frac{4}{5}} + 1250 x^{\frac{3}{5}} + 250 x^{\frac{2}{5}} \cdot - 1 + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.21

Mutltipliziere $- 1$ mit $250$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x - 3125 x^{\frac{4}{5}} + 1250 x^{\frac{3}{5}} - 250 x^{\frac{2}{5}} + 5 (5 x^{\frac{1}{5}}) {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.22

Mutltipliziere $5$ mit $5$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x - 3125 x^{\frac{4}{5}} + 1250 x^{\frac{3}{5}} - 250 x^{\frac{2}{5}} + 25 x^{\frac{1}{5}} {(- 1)}^{4} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.23

Potenziere $- 1$ mit $4$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x - 3125 x^{\frac{4}{5}} + 1250 x^{\frac{3}{5}} - 250 x^{\frac{2}{5}} + 25 x^{\frac{1}{5}} \cdot 1 + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.24

Mutltipliziere $25$ mit $1$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x - 3125 x^{\frac{4}{5}} + 1250 x^{\frac{3}{5}} - 250 x^{\frac{2}{5}} + 25 x^{\frac{1}{5}} + {(- 1)}^{5}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.2.25

Potenziere $- 1$ mit $5$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{1 + 3125 x - 3125 x^{\frac{4}{5}} + 1250 x^{\frac{3}{5}} - 250 x^{\frac{2}{5}} + 25 x^{\frac{1}{5}} - 1}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.3

Subtrahiere $1$ von $1$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{3125 x - 3125 x^{\frac{4}{5}} + 1250 x^{\frac{3}{5}} - 250 x^{\frac{2}{5}} + 25 x^{\frac{1}{5}} + 0}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.4

Addiere $3125 x - 3125 x^{\frac{4}{5}} + 1250 x^{\frac{3}{5}} - 250 x^{\frac{2}{5}} + 25 x^{\frac{1}{5}}$ und $0$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{3125 x - 3125 x^{\frac{4}{5}} + 1250 x^{\frac{3}{5}} - 250 x^{\frac{2}{5}} + 25 x^{\frac{1}{5}}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.5

Stelle die Terme um.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{3125 x + 1250 x^{\frac{3}{5}} + 25 x^{\frac{1}{5}} - 250 x^{\frac{2}{5}} - 3125 x^{\frac{4}{5}}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.6

Schreibe $3125 x + 1250 x^{\frac{3}{5}} + 25 x^{\frac{1}{5}} - 250 x^{\frac{2}{5}} - 3125 x^{\frac{4}{5}}$ in eine faktorisierte Form um.

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Schritt 5.2.3.7.1.6.1

Faktorisiere $25 x^{\frac{1}{5}}$ aus $3125 x + 1250 x^{\frac{3}{5}} + 25 x^{\frac{1}{5}} - 250 x^{\frac{2}{5}} - 3125 x^{\frac{4}{5}}$ heraus.

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Schritt 5.2.3.7.1.6.1.1

Faktorisiere $25 x^{\frac{1}{5}}$ aus $3125 x$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{25 x^{\frac{1}{5}} (125 x^{\frac{4}{5}}) + 1250 x^{\frac{3}{5}} + 25 x^{\frac{1}{5}} - 250 x^{\frac{2}{5}} - 3125 x^{\frac{4}{5}}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.6.1.2

Faktorisiere $25 x^{\frac{1}{5}}$ aus $1250 x^{\frac{3}{5}}$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{25 x^{\frac{1}{5}} (125 x^{\frac{4}{5}}) + 25 x^{\frac{1}{5}} (50 x^{\frac{2}{5}}) + 25 x^{\frac{1}{5}} - 250 x^{\frac{2}{5}} - 3125 x^{\frac{4}{5}}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.6.1.3

Faktorisiere $25 x^{\frac{1}{5}}$ aus $25 x^{\frac{1}{5}}$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{25 x^{\frac{1}{5}} (125 x^{\frac{4}{5}}) + 25 x^{\frac{1}{5}} (50 x^{\frac{2}{5}}) + 25 x^{\frac{1}{5}} (1) - 250 x^{\frac{2}{5}} - 3125 x^{\frac{4}{5}}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.6.1.4

Faktorisiere $25 x^{\frac{1}{5}}$ aus $- 250 x^{\frac{2}{5}}$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{25 x^{\frac{1}{5}} (125 x^{\frac{4}{5}}) + 25 x^{\frac{1}{5}} (50 x^{\frac{2}{5}}) + 25 x^{\frac{1}{5}} (1) + 25 x^{\frac{1}{5}} (- 10 x^{\frac{1}{5}}) - 3125 x^{\frac{4}{5}}}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.6.1.5

Faktorisiere $25 x^{\frac{1}{5}}$ aus $- 3125 x^{\frac{4}{5}}$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{25 x^{\frac{1}{5}} (125 x^{\frac{4}{5}}) + 25 x^{\frac{1}{5}} (50 x^{\frac{2}{5}}) + 25 x^{\frac{1}{5}} (1) + 25 x^{\frac{1}{5}} (- 10 x^{\frac{1}{5}}) + 25 x^{\frac{1}{5}} (- 125 x^{\frac{3}{5}})}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.6.1.6

Faktorisiere $25 x^{\frac{1}{5}}$ aus $25 x^{\frac{1}{5}} (125 x^{\frac{4}{5}}) + 25 x^{\frac{1}{5}} (50 x^{\frac{2}{5}})$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{25 x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}}) + 25 x^{\frac{1}{5}} (1) + 25 x^{\frac{1}{5}} (- 10 x^{\frac{1}{5}}) + 25 x^{\frac{1}{5}} (- 125 x^{\frac{3}{5}})}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.6.1.7

Faktorisiere $25 x^{\frac{1}{5}}$ aus $25 x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}}) + 25 x^{\frac{1}{5}} (1)$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{25 x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}} + 1) + 25 x^{\frac{1}{5}} (- 10 x^{\frac{1}{5}}) + 25 x^{\frac{1}{5}} (- 125 x^{\frac{3}{5}})}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.6.1.8

Faktorisiere $25 x^{\frac{1}{5}}$ aus $25 x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}} + 1) + 25 x^{\frac{1}{5}} (- 10 x^{\frac{1}{5}})$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{25 x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}} + 1 - 10 x^{\frac{1}{5}}) + 25 x^{\frac{1}{5}} (- 125 x^{\frac{3}{5}})}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.6.1.9

Faktorisiere $25 x^{\frac{1}{5}}$ aus $25 x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}} + 1 - 10 x^{\frac{1}{5}}) + 25 x^{\frac{1}{5}} (- 125 x^{\frac{3}{5}})$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{25 x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}} + 1 - 10 x^{\frac{1}{5}} - 125 x^{\frac{3}{5}})}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.1.6.2

Stelle die Terme um.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{25 x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}} - 10 x^{\frac{1}{5}} - 125 x^{\frac{3}{5}} + 1)}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.2

Faktorisiere $25$ aus $25 x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}} - 10 x^{\frac{1}{5}} - 125 x^{\frac{3}{5}} + 1)$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{25 (x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}} - 10 x^{\frac{1}{5}} - 125 x^{\frac{3}{5}} + 1))}{3125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.3

Kürze die gemeinsamen Faktoren.

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Schritt 5.2.3.7.3.1

Faktorisiere $25$ aus $3125$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{25 (x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}} - 10 x^{\frac{1}{5}} - 125 x^{\frac{3}{5}} + 1))}{25 \cdot 125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.7.3.2

Kürze den gemeinsamen Faktor.

Schritt 5.2.3.7.3.3

Forme den Ausdruck um.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}} - 10 x^{\frac{1}{5}} - 125 x^{\frac{3}{5}} + 1)}{125} + \frac{x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.8

Vereinige die Zähler über dem gemeinsamen Nenner.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}} - 10 x^{\frac{1}{5}} - 125 x^{\frac{3}{5}} + 1) + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9

Vereinfache jeden Term.

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Schritt 5.2.3.9.1

Wende das Distributivgesetz an.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{1}{5}} (125 x^{\frac{4}{5}}) + x^{\frac{1}{5}} (50 x^{\frac{2}{5}}) + x^{\frac{1}{5}} (- 10 x^{\frac{1}{5}}) + x^{\frac{1}{5}} (- 125 x^{\frac{3}{5}}) + x^{\frac{1}{5}} \cdot 1 + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.2

Vereinfache.

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Schritt 5.2.3.9.2.1

Schreibe neu unter Anwendung des Kommutativgesetzes der Multiplikation.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x^{\frac{1}{5}} x^{\frac{4}{5}} + x^{\frac{1}{5}} (50 x^{\frac{2}{5}}) + x^{\frac{1}{5}} (- 10 x^{\frac{1}{5}}) + x^{\frac{1}{5}} (- 125 x^{\frac{3}{5}}) + x^{\frac{1}{5}} \cdot 1 + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.2.2

Schreibe neu unter Anwendung des Kommutativgesetzes der Multiplikation.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x^{\frac{1}{5}} x^{\frac{4}{5}} + 50 x^{\frac{1}{5}} x^{\frac{2}{5}} + x^{\frac{1}{5}} (- 10 x^{\frac{1}{5}}) + x^{\frac{1}{5}} (- 125 x^{\frac{3}{5}}) + x^{\frac{1}{5}} \cdot 1 + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.2.3

Schreibe neu unter Anwendung des Kommutativgesetzes der Multiplikation.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x^{\frac{1}{5}} x^{\frac{4}{5}} + 50 x^{\frac{1}{5}} x^{\frac{2}{5}} - 10 x^{\frac{1}{5}} x^{\frac{1}{5}} + x^{\frac{1}{5}} (- 125 x^{\frac{3}{5}}) + x^{\frac{1}{5}} \cdot 1 + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.2.4

Schreibe neu unter Anwendung des Kommutativgesetzes der Multiplikation.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x^{\frac{1}{5}} x^{\frac{4}{5}} + 50 x^{\frac{1}{5}} x^{\frac{2}{5}} - 10 x^{\frac{1}{5}} x^{\frac{1}{5}} - 125 x^{\frac{1}{5}} x^{\frac{3}{5}} + x^{\frac{1}{5}} \cdot 1 + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.2.5

Mutltipliziere $x^{\frac{1}{5}}$ mit $1$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x^{\frac{1}{5}} x^{\frac{4}{5}} + 50 x^{\frac{1}{5}} x^{\frac{2}{5}} - 10 x^{\frac{1}{5}} x^{\frac{1}{5}} - 125 x^{\frac{1}{5}} x^{\frac{3}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.3

Vereinfache jeden Term.

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Schritt 5.2.3.9.3.1

Multipliziere $x^{\frac{1}{5}}$ mit $x^{\frac{4}{5}}$ durch Addieren der Exponenten.

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Schritt 5.2.3.9.3.1.1

Bewege $x^{\frac{4}{5}}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 (x^{\frac{4}{5}} x^{\frac{1}{5}}) + 50 x^{\frac{1}{5}} x^{\frac{2}{5}} - 10 x^{\frac{1}{5}} x^{\frac{1}{5}} - 125 x^{\frac{1}{5}} x^{\frac{3}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.3.1.2

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x^{\frac{4}{5} + \frac{1}{5}} + 50 x^{\frac{1}{5}} x^{\frac{2}{5}} - 10 x^{\frac{1}{5}} x^{\frac{1}{5}} - 125 x^{\frac{1}{5}} x^{\frac{3}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.3.1.3

Vereinige die Zähler über dem gemeinsamen Nenner.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x^{\frac{4 + 1}{5}} + 50 x^{\frac{1}{5}} x^{\frac{2}{5}} - 10 x^{\frac{1}{5}} x^{\frac{1}{5}} - 125 x^{\frac{1}{5}} x^{\frac{3}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.3.1.4

Addiere $4$ und $1$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x^{\frac{5}{5}} + 50 x^{\frac{1}{5}} x^{\frac{2}{5}} - 10 x^{\frac{1}{5}} x^{\frac{1}{5}} - 125 x^{\frac{1}{5}} x^{\frac{3}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.3.1.5

Dividiere $5$ durch $5$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x + 50 x^{\frac{1}{5}} x^{\frac{2}{5}} - 10 x^{\frac{1}{5}} x^{\frac{1}{5}} - 125 x^{\frac{1}{5}} x^{\frac{3}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.3.2

Vereinfache $125 x^{1}$ .

Schritt 5.2.3.9.3.3

Multipliziere $x^{\frac{1}{5}}$ mit $x^{\frac{2}{5}}$ durch Addieren der Exponenten.

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Schritt 5.2.3.9.3.3.1

Bewege $x^{\frac{2}{5}}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x + 50 (x^{\frac{2}{5}} x^{\frac{1}{5}}) - 10 x^{\frac{1}{5}} x^{\frac{1}{5}} - 125 x^{\frac{1}{5}} x^{\frac{3}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.3.3.2

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x + 50 x^{\frac{2}{5} + \frac{1}{5}} - 10 x^{\frac{1}{5}} x^{\frac{1}{5}} - 125 x^{\frac{1}{5}} x^{\frac{3}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.3.3.3

Vereinige die Zähler über dem gemeinsamen Nenner.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x + 50 x^{\frac{2 + 1}{5}} - 10 x^{\frac{1}{5}} x^{\frac{1}{5}} - 125 x^{\frac{1}{5}} x^{\frac{3}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.3.3.4

Addiere $2$ und $1$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x + 50 x^{\frac{3}{5}} - 10 x^{\frac{1}{5}} x^{\frac{1}{5}} - 125 x^{\frac{1}{5}} x^{\frac{3}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.3.4

Multipliziere $x^{\frac{1}{5}}$ mit $x^{\frac{1}{5}}$ durch Addieren der Exponenten.

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Schritt 5.2.3.9.3.4.1

Bewege $x^{\frac{1}{5}}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x + 50 x^{\frac{3}{5}} - 10 (x^{\frac{1}{5}} x^{\frac{1}{5}}) - 125 x^{\frac{1}{5}} x^{\frac{3}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.3.4.2

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x + 50 x^{\frac{3}{5}} - 10 x^{\frac{1}{5} + \frac{1}{5}} - 125 x^{\frac{1}{5}} x^{\frac{3}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.3.4.3

Vereinige die Zähler über dem gemeinsamen Nenner.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x + 50 x^{\frac{3}{5}} - 10 x^{\frac{1 + 1}{5}} - 125 x^{\frac{1}{5}} x^{\frac{3}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.3.4.4

Addiere $1$ und $1$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x + 50 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} - 125 x^{\frac{1}{5}} x^{\frac{3}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.3.5

Multipliziere $x^{\frac{1}{5}}$ mit $x^{\frac{3}{5}}$ durch Addieren der Exponenten.

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Schritt 5.2.3.9.3.5.1

Bewege $x^{\frac{3}{5}}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x + 50 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} - 125 (x^{\frac{3}{5}} x^{\frac{1}{5}}) + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.3.5.2

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x + 50 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} - 125 x^{\frac{3}{5} + \frac{1}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.3.5.3

Vereinige die Zähler über dem gemeinsamen Nenner.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x + 50 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} - 125 x^{\frac{3 + 1}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.3.9.3.5.4

Addiere $3$ und $1$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{125 x + 50 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} - 125 x^{\frac{4}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.4

Vereinfache den Zähler.

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Schritt 5.2.4.1

Faktorisiere $x^{\frac{1}{5}}$ aus $125 x + 50 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} - 125 x^{\frac{4}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)$ heraus.

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Schritt 5.2.4.1.1

Faktorisiere $x^{\frac{1}{5}}$ aus $125 x$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{1}{5}} (125 x^{\frac{4}{5}}) + 50 x^{\frac{3}{5}} - 10 x^{\frac{2}{5}} - 125 x^{\frac{4}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.4.1.2

Faktorisiere $x^{\frac{1}{5}}$ aus $50 x^{\frac{3}{5}}$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{1}{5}} (125 x^{\frac{4}{5}}) + x^{\frac{1}{5}} (50 x^{\frac{2}{5}}) - 10 x^{\frac{2}{5}} - 125 x^{\frac{4}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.4.1.3

Faktorisiere $x^{\frac{1}{5}}$ aus $- 10 x^{\frac{2}{5}}$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{1}{5}} (125 x^{\frac{4}{5}}) + x^{\frac{1}{5}} (50 x^{\frac{2}{5}}) + x^{\frac{1}{5}} (- 10 x^{\frac{1}{5}}) - 125 x^{\frac{4}{5}} + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.4.1.4

Faktorisiere $x^{\frac{1}{5}}$ aus $- 125 x^{\frac{4}{5}}$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{1}{5}} (125 x^{\frac{4}{5}}) + x^{\frac{1}{5}} (50 x^{\frac{2}{5}}) + x^{\frac{1}{5}} (- 10 x^{\frac{1}{5}}) + x^{\frac{1}{5}} (- 125 x^{\frac{3}{5}}) + x^{\frac{1}{5}} + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.4.1.5

Multipliziere mit $1$ .

Schritt 5.2.4.1.6

Faktorisiere $x^{\frac{1}{5}}$ aus $x^{\frac{1}{5}} (125 x^{\frac{4}{5}}) + x^{\frac{1}{5}} (50 x^{\frac{2}{5}})$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}}) + x^{\frac{1}{5}} (- 10 x^{\frac{1}{5}}) + x^{\frac{1}{5}} (- 125 x^{\frac{3}{5}}) + x^{\frac{1}{5}} \cdot 1 + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.4.1.7

Faktorisiere $x^{\frac{1}{5}}$ aus $x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}}) + x^{\frac{1}{5}} (- 10 x^{\frac{1}{5}})$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}} - 10 x^{\frac{1}{5}}) + x^{\frac{1}{5}} (- 125 x^{\frac{3}{5}}) + x^{\frac{1}{5}} \cdot 1 + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.4.1.8

Faktorisiere $x^{\frac{1}{5}}$ aus $x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}} - 10 x^{\frac{1}{5}}) + x^{\frac{1}{5}} (- 125 x^{\frac{3}{5}})$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}} - 10 x^{\frac{1}{5}} - 125 x^{\frac{3}{5}}) + x^{\frac{1}{5}} \cdot 1 + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.4.1.9

Faktorisiere $x^{\frac{1}{5}}$ aus $x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}} - 10 x^{\frac{1}{5}} - 125 x^{\frac{3}{5}}) + x^{\frac{1}{5}} \cdot 1$ heraus.

Schritt 5.2.4.1.10

Faktorisiere $x^{\frac{1}{5}}$ aus $x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}} - 10 x^{\frac{1}{5}} - 125 x^{\frac{3}{5}} + 1) + x^{\frac{1}{5}} (125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)$ heraus.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 50 x^{\frac{2}{5}} - 10 x^{\frac{1}{5}} - 125 x^{\frac{3}{5}} + 1 + 125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 50 x^{\frac{2}{5}} - 1)}{125}$

Schritt 5.2.4.2

Subtrahiere $50 x^{\frac{2}{5}}$ von $50 x^{\frac{2}{5}}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{1}{5}} (125 x^{\frac{4}{5}} - 10 x^{\frac{1}{5}} - 125 x^{\frac{3}{5}} + 1 + 125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} + 0 - 1)}{125}$

Schritt 5.2.4.3

Addiere $125 x^{\frac{4}{5}}$ und $0$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{1}{5}} (125 x^{\frac{4}{5}} - 10 x^{\frac{1}{5}} - 125 x^{\frac{3}{5}} + 1 + 125 x^{\frac{3}{5}} + 10 x^{\frac{1}{5}} - 1)}{125}$

Schritt 5.2.4.4

Addiere $- 10 x^{\frac{1}{5}}$ und $10 x^{\frac{1}{5}}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{1}{5}} (125 x^{\frac{4}{5}} - 125 x^{\frac{3}{5}} + 1 + 125 x^{\frac{3}{5}} + 0 - 1)}{125}$

Schritt 5.2.4.5

Addiere $125 x^{\frac{4}{5}}$ und $0$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{1}{5}} (125 x^{\frac{4}{5}} - 125 x^{\frac{3}{5}} + 1 + 125 x^{\frac{3}{5}} - 1)}{125}$

Schritt 5.2.4.6

Addiere $- 125 x^{\frac{3}{5}}$ und $125 x^{\frac{3}{5}}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 0 + 1 - 1)}{125}$

Schritt 5.2.4.7

Addiere $125 x^{\frac{4}{5}}$ und $0$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 1 - 1)}{125}$

Schritt 5.2.4.8

Subtrahiere $1$ von $1$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{1}{5}} (125 x^{\frac{4}{5}} + 0)}{125}$

Schritt 5.2.4.9

Addiere $125 x^{\frac{4}{5}}$ und $0$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{1}{5}} \cdot (125 x^{\frac{4}{5}})}{125}$

Schritt 5.2.4.10

Kombiniere Exponenten.

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Schritt 5.2.4.10.1

Multipliziere $x^{\frac{1}{5}}$ mit $x^{\frac{4}{5}}$ durch Addieren der Exponenten.

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Schritt 5.2.4.10.1.1

Bewege $x^{\frac{4}{5}}$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{4}{5}} x^{\frac{1}{5}} \cdot 125}{125}$

Schritt 5.2.4.10.1.2

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{4}{5} + \frac{1}{5}} \cdot 125}{125}$

Schritt 5.2.4.10.1.3

Vereinige die Zähler über dem gemeinsamen Nenner.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{4 + 1}{5}} \cdot 125}{125}$

Schritt 5.2.4.10.1.4

Addiere $4$ und $1$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x^{\frac{5}{5}} \cdot 125}{125}$

Schritt 5.2.4.10.1.5

Dividiere $5$ durch $5$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x \cdot 125}{125}$

Schritt 5.2.4.10.2

Vereinfache $x^{1} \cdot 125$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x \cdot 125}{125}$

Schritt 5.2.5

Kürze den gemeinsamen Faktor von $125$ .

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Schritt 5.2.5.1

Kürze den gemeinsamen Faktor.

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = \frac{x \cdot 125}{125}$

Schritt 5.2.5.2

Dividiere $x$ durch $1$ .

$f^{- 1} (10 x^{\frac{1}{5}} - 2) = x$

Schritt 5.3

Berechne $f (f^{- 1} (x))$ .

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Schritt 5.3.1

Bilde die verkettete Ergebnisfunktion.

$f (f^{- 1} (x))$

Schritt 5.3.2

Berechne $f (\frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{x^{3}}{2500} + \frac{x^{4}}{10000} + \frac{x^{5}}{100000})$ durch Einsetzen des Wertes von $f^{- 1}$ in $f$ .

$f (\frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{x^{3}}{2500} + \frac{x^{4}}{10000} + \frac{x^{5}}{100000}) = 10 {(\frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{x^{3}}{2500} + \frac{x^{4}}{10000} + \frac{x^{5}}{100000})}^{\frac{1}{5}} - 2$

Schritt 5.3.3

Bewege $\frac{1}{3125}$ .

$f (\frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{x^{3}}{2500} + \frac{x^{4}}{10000} + \frac{x^{5}}{100000}) = 10 {(\frac{x}{1250} + \frac{x^{2}}{1250} + \frac{x^{3}}{2500} + \frac{x^{4}}{10000} + \frac{x^{5}}{100000} + \frac{1}{3125})}^{\frac{1}{5}} - 2$

Schritt 5.3.4

Bewege $\frac{x}{1250}$ .

$f (\frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{x^{3}}{2500} + \frac{x^{4}}{10000} + \frac{x^{5}}{100000}) = 10 {(\frac{x^{2}}{1250} + \frac{x^{3}}{2500} + \frac{x^{4}}{10000} + \frac{x^{5}}{100000} + \frac{x}{1250} + \frac{1}{3125})}^{\frac{1}{5}} - 2$

Schritt 5.3.5

Bewege $\frac{x^{2}}{1250}$ .

$f (\frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{x^{3}}{2500} + \frac{x^{4}}{10000} + \frac{x^{5}}{100000}) = 10 {(\frac{x^{3}}{2500} + \frac{x^{4}}{10000} + \frac{x^{5}}{100000} + \frac{x^{2}}{1250} + \frac{x}{1250} + \frac{1}{3125})}^{\frac{1}{5}} - 2$

Schritt 5.3.6

Bewege $\frac{x^{3}}{2500}$ .

$f (\frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{x^{3}}{2500} + \frac{x^{4}}{10000} + \frac{x^{5}}{100000}) = 10 {(\frac{x^{4}}{10000} + \frac{x^{5}}{100000} + \frac{x^{3}}{2500} + \frac{x^{2}}{1250} + \frac{x}{1250} + \frac{1}{3125})}^{\frac{1}{5}} - 2$

Schritt 5.3.7

Stelle $\frac{x^{4}}{10000}$ und $\frac{x^{5}}{100000}$ um.

$f (\frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{x^{3}}{2500} + \frac{x^{4}}{10000} + \frac{x^{5}}{100000}) = 10 {(\frac{x^{5}}{100000} + \frac{x^{4}}{10000} + \frac{x^{3}}{2500} + \frac{x^{2}}{1250} + \frac{x}{1250} + \frac{1}{3125})}^{\frac{1}{5}} - 2$

Schritt 5.4

Da $f^{- 1} (f (x)) = x$ und $f (f^{- 1} (x)) = x$ gleich sind, ist $f^{- 1} (x) = \frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{x^{3}}{2500} + \frac{x^{4}}{10000} + \frac{x^{5}}{100000}$ die inverse Funktion (Umkehrfunktion) von $f (x) = 10 x^{\frac{1}{5}} - 2$ .

$f^{- 1} (x) = \frac{1}{3125} + \frac{x}{1250} + \frac{x^{2}}{1250} + \frac{x^{3}}{2500} + \frac{x^{4}}{10000} + \frac{x^{5}}{100000}$