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$[\begin{array}{c} 5 & 11 & 3 \end{array}] - [\begin{array}{c} 2 & 0 & 2 \end{array}] = [\begin{array}{c} 3 & x & 1 \end{array}]$

خطوة 1

اطرح العناصر المتناظرة.

$[\begin{array}{c} 5 - 2 & 11 - 0 & 3 - 2 \end{array}] = [\begin{array}{c} 3 & x & 1 \end{array}]$

خطوة 2

Simplify each element.

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خطوة 2.1

اطرح $2$ من $5$ .

$[\begin{array}{c} 3 & 11 - 0 & 3 - 2 \end{array}] = [\begin{array}{c} 3 & x & 1 \end{array}]$

خطوة 2.2

اطرح $0$ من $11$ .

$[\begin{array}{c} 3 & 11 & 3 - 2 \end{array}] = [\begin{array}{c} 3 & x & 1 \end{array}]$

خطوة 2.3

اطرح $2$ من $3$ .

$[\begin{array}{c} 3 & 11 & 1 \end{array}] = [\begin{array}{c} 3 & x & 1 \end{array}]$

خطوة 3

Write as a linear system of equations.

$3 = 3$

$11 = x$

$1 = 1$

خطوة 4

Since $1 = 1$ is always true, the matrix equation has infinite solutions.

Infinite solutions satisfying $11 = x$ .