Основы мат. анализа Примеры

$(1, - 2)$ , $(3, 6)$

Step 1

Since for each value of $x$ there is one and only one value of $y$ , the given relation $(1, - 2), (3, 6)$ is a function.

The relation is a function.

Step 2

Since the relation is a function and for each value of $y$ there is one and only one value of $x$ , the given relation $(1, - 2), (3, 6)$ is a one-to-one function.

The relation is a one-to-one function.

Введите СВОЮ задачу