Алгебра Примеры

$47$

Step 1

A perfect square number is an integer that is the square of another integer. $\sqrt{47} \approx 6.8556546$ , which is not an integer number.

$\sqrt{47} \approx 6.8556546$

Step 2

Since $47$ can't be the square of another integer, it is not a perfect square number.

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$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$